In the triangle ABC, the point
X divides BC such that BX:XC=2:3. The point Y divides CA such that
CY:YA=1:2. O is the intersection point
of AX and BY. The area of triangle COY
is ‘a’, that of triangle COX is ‘b’.
Find the area of the quadrilateral OXBZ, where Z is the point where CO meets AB.
2 comments:
Remember a theorem that connects the ratios in which three points on the sides divide them, provided the lines joining these points to the opposite vertices are concurrent?
Click Here for the solution
You can download the pdf file with solution.
Please post your comments
Post a Comment