When divided by two, the number should have even powers in its prime factorisation. When divided by three, it should have powers divisible by 3. The number should be as small as possible. So, the number must be expressed as 2^a.3^b where a must be smallest odd number more than 1, ie 3 and b must smallest number that leaves remainder 1 when divided by 3 ie, 4. Hence the number is 2^3.3^4=648
4 comments:
Is it 648 sir?
right
wats the solution?is there any short cut to find ans?
When divided by two, the number should have even powers in its prime factorisation. When divided by three, it should have powers divisible by 3. The number should be as small as possible. So, the number must be expressed as 2^a.3^b where a must be smallest odd number more than 1, ie 3 and b must smallest number that leaves remainder 1 when divided by 3 ie, 4.
Hence the number is 2^3.3^4=648
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